On a shelf in irmas garage are 3 cans of red paint 7 cans of blue paint 2 cans of yellow paint 8 cans of green paint Irma will randomly choose one can of paint. What is the probability that she will choose a can of blue paint

7/20

Step-by-step explanation:

Cans of red paint= 3

Cans of blue paint= 7

Cans of yellow paint= 2

Cans of green paint= 8

Total cans of paint= 3+7+2+8 = 20

Probability of Irma choosing one blue paint will be total number of paints divided by the total cans of paints.

= Cans of blue paint / Total cans of paint

= 7/20

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.