Suppose you carry out a significance test of H0: μ = 7 versus Ha: μ ≠ 7 based on sample size n = 28 and obtain t = 1.45. Find the p-value for this test. What conclusion can you draw at the 5% significance level? Explain.

Possible answers:
The p-value is 0.0793. We reject H0 at the 5% significance level because the p-value 0.0793 is greater than 0.05.
The p-value is 0.0793. We fail to reject H0 at the 5% significance level because the p-value 0.0793 is greater than 0.05.
The p-value is 0.4207. We fail to reject H0 at the 5% significance level because the p-value 0.4207 is greater than 0.05.
The p-value is 0.1586. We fail to reject H0 at the 5% significance level because the p-value 0.1586 is greater than 0.05.
The p-value is 0.1586. We reject H0 at the 5% significance level because the p-value 0.1586 is greater than 0.05.

answer: city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

since we have given that

total annual rainfall a city record = 40 inches

this year, total rainfall recorded = 37.6 inches

number of inches of rainfall   is needed to match the record of 40 inches is given by

hence, city needs 2.4 inches of rainfall more to match the record of 40 inches.

-6 is the correct option from the above given options

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west