What is the equation of the circle with center (4. -4) that passes through the point (1, 0)?
(x - 4)2 + (y + 4)2 = 25
(x-4)2 + y - 4)2 = 25
(x+4)2 + (y + 4)2 = 5
(x-4)²-(y + 4)² = 25

Correct A

equation of a circle having a centre (4, -4):

(x-4)² + (y+4)² =r²

now, (1, 0) passes through the circle.

Then, (1-4)² + (0+4)² =r²

So,  9 + 16 =r² =25

(x-4)² + (y+4)² =25

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

-60.75

step-by-step explanation:

just add the numbers then put the negative sign on it