Number from 1 to 99 is written on a card making a pack of 99 cards. What is the probability of randomly selecting a card where the number contains at least one digit 1

(19/99) = 0.192

Step-by-step explanation:

Numbers 1 to 99, that is 99 numbers (obtained through the equation for the nth term of an AP)

L = a + (n-1) d

L = nth term = 99

a = first term = 1

n = number of terms = ?

d = common difference = 1

99 = 1 + (n-1)1

n = 99

Sample space = 99

The numbers that include at least, a 1 are

1, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 21, 31, 41, 51, 61, 71, 81, 91

19 numbers.

Probability of randomly selecting a card where the number contains at least one digit 1 from 1 to 99 = (19/99) = 0.192

Hope this Helps!!!

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180