One trampoline has a diameter of 10 feet. A larger trampoline has a diameter of 14 feet. How much greater is the area of the larger trampoline? Use 3.14 for π.

The second trampolline is 75.36 feet^2 greater than the first one.

Step-by-step explanation:

Assuming the trampolines are circullar their area will be given by:

A = \pi*(r^2)

The radius of a circle is r = d/2. So for the first trampoline we have:

A_1 = 3.14*[(10/2)^2] = 3.14*(25) = 78.5 feet^2

For the second trampoline we have:

A_2 = 3.14*[(14/2)^2] = 3.14*(49) = 153.86 feet^2

Difference between the areas:

A_2 - A_1 = 153.86 - 78.5 = 75.36 feet^2

From this we can say that the second trampolline is 75.36 feet^2 greater than the first one.

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)