Write an equation in slope-intercept form of the line with the parametric equations x = -4t + 3 and y = 5t - 3.
A. y = 5/3x + 4/3
B. y = -5/3x + 4/3
C. y = 5/4x + 3/4
D. y = -5/4x + 3/4

D

Step-by-step explanation:

Since both equations have the variable t, rewrite t in terms of x

x = -4t + 3

4t = 3 - x

t =

Now you can plug t into y

y = 5t - 3

y =

y =

y =

y =

y =

D

Step-by-step explanation:

x = -4t + 3

4t = 3 - x

t = (3 - x)/4

y = 5t - 3

y = 5(3 - x)/4 - 3

y = 15/4 - 5x/4 - 3

y = -5x/4 + 3/4

y = (-5/4)x + 3/4

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb