Please help
Trig: Laws of Cosines.
In Δ PQR , side p =12, side r =6 and m < Q= 92* . Find side ' q' to the nearest integer.

Step-by-step explanation:

we would apply the law of Cosines which is expressed as

a² = b² + c² - 2abCosA

Where a,b and c are the length of each side of the triangle and A is the angle corresponding to a. Likening the expression to the given triangle, it becomes

q² = p² + r² - 2(p × r)CosQ

q² = 12² + 6² - 2(12 × 6)Cos92

q² = 144 + 36 - 2(72)Cos92

q² = 180 - 144 × - 0.0349

q² = 180 + 5.0256

q² = 185.0256

q = √185.0256

q = 13.6 to the nearest integer

13.6 units

Step-by-step explanation:

q² = 12² + 6² - 2(12)(6)cos(92)

q² = 185.0255275252

q = 13.6024088869

the correct answer to your question is a. 4^4

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27

step-by-step explanation: