During his last 5 jobs, an electrician used the following amounts of cable:

12.995 m
7.505 m
10.08 m
6.95 m
9.75 m
By rounding each amount to 1 decimal place, what was the total amount of cable used?

The total amount of cable used is 47.4m

Explanation:

Given:

Amounts of cable used that has to be rounded off to 1 decimal place:

12.995 m  ≈ 13.0 m

7.505 m  ≈ 7.5m

10.08 m  ≈ 10.1 m

6.95 m  ≈ 7.0 m

9.75 m ≈ 9.8 m

Total amount of cable used = 13m + 7.5m + 10.1m + 7m + 9.8m

                                              = 47.4m

Therefore, total amount of cable used is 47.4m

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: