ΔRST and ΔXYZ are equilateral triangles. The ratio of the perimeter of ΔRST to the perimeter of ΔXYZ is 1 to 3. The area of ΔRST is 10.825 square inches. What is the area of ΔXYZ? (round to nearest tenth)

≈ 97.4 in²

Step-by-step explanation:

Given that the ratio of the perimeter = a : b

then ratio of areas = a² : b²

The ratio of perimeter = 1 : 3 , thus

ratio of area = 1² : 3² = 1 : 9

The area of Δ XYZ is therefore 9 times the area of Δ RST

area of Δ XYZ = 9 × 10.825 = 97.425 ≈ 97.4 ( to the nearest tenth )

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !