If the cos of angle x is 8 over 17, and the triangle was dilated to be two times as big as the original, what would be the value of the cos of x for the dilated triangle? hint: use the slash symbol ( / ) to represent the fraction bar and enter the fraction with no spaces.

8/17 is correct.

Step-by-step explanation:

Got i Correct on my quiz.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer