Find the perimeter of a rectangle with a width of 2 times the square root of 5 plus 3 times the square root of 11 and a length of 3 times the square root of 5 minus the square root of 11

Perimeter = 10√5 + 4√11

Step-by-step explanation:

The width of the rectangle is 2 times the square root of 5 plus 3 times the square root of 11. It means that

W = 2√5 + 3√11

The length of the rectangle is 3 times the square root of 5 minus the square root of 11. It means that

L = 3√5 - √11

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(Length+ Width)

Therefore,

Perimeter = 2(2√5 + 3√11 + 3√5 - √11)

Perimeter = 2(2√5 + 3√5 + 3√11 - √11)

Perimeter = 2(5√5 + 2√11)

Expanding the brackets, it becomes

Perimeter = 10√5 + 4√11

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation