What value of x makes the equation true?

x=3

Step-by-step explanation:

(-11)^x * (-11) ^4 = (-11)^10/ (-11)^3

We know a^b * a^c = a^(b+c)

(-11)^(x +4) = (-11)^10/ (-11)^3

We know a^b / a^c = a^(b-c)

(-11)^(x +4) = (-11)^(10 -3)

(-11)^(x +4) = (-11)^(7)

The bases are the same so the exponents are the same

x+4 = 7

Subtract 4 from each side

x+4-4 = 7-4

x =3

X is 3

Step-by-step explanation:

You can make your equation simpler by solving the one on the right:

( -11 )^x times ( -11)^4 = ( -11 )^7

Then 7 - 4 is 3 so the exponent must be 3.

idk wbu

step-by-step explanation: