A pool measuring 10 meters by 26 meters is surrounded by a path of uniform width if the area of the pool and the path combined is 612 square meters what is the width of the path

the width of the path is 4 meters.

Step-by-step explanation:

Let x represent the width of the path.

A pool measuring 10 meters by 26 meters is surrounded by a path of uniform width. It means that the combined length of the pool and the path is (10 + 2x) meters.

Also, the combined width of the pool and the path is (26 + 2x) meters.

if the area of the pool and the path combined is 612 square meters, it means that

(10 + 2x)(26 + 2x) = 612

260 + 20x + 52x + 4x² = 612

4x² + 72x + 260 - 612 = 0

4x² + 72x - 352 = 0

Dividing through by 4, it becomes

x² + 18x - 88 = 0

x² + 22x - 4x - 88 = 0

x(x + 22) - 4(x + 22) = 0

x - 4 = 0 or x + 22 = 0

x = 4 or x = - 22

Since the width cannot be negative, then x = 4

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1

step-by-step explanation: