How much greater is the surface area of a basketball with a radius of 4.7244 inches than the surface area of a tennis ball with a radius of 1.2598 inches? round to the nearest hundredth

The surface area of a sphere is the product when 4 is multiplied to π and square of radius. For the basketball, 
                                SA = 4π x (4.7244 in)² = 280.48 in²
For the tennis ball,
                                SA = 4π x (1.2598 in)² = 19.944 in²
To answer the question, determine the difference of their surface area. That is,
                             280.48 in² - 19.944 in² = 260.90 in²