One issue of a journal has 3 full-page ads and 5 half-page ads, generating $6340 in advertising
revenue. The next issue has 4 full-page ads and 4 half-page ads, resulting in advertising revenue
of $6625. Determine the advertising rates in this journal for full-page and half-page ads.

To help solve this problem, we need to create a system of equations.

let x = cost of one full-page ad

let y = cost of half-page ad

First issue: 3x + 5y = 6340

second issue: 4x + 4y = 6625.

Multiply the first equation by 4 and the second equation by -3

First issue: 12x + 20y = 25,360

Second issue -12x - 12y = - 19,875.

Add both equations together.

New equation: 8y = 5485.

Divide both sides by 8 to solve for y

y = $685.63.

Plug $685.63 into one of our original equations.

3x + 5(685.63) = 6340

Multiply 5 by 685.63

3x + 3428.15 = 6340.

Subtract 3428.15 from both sides

3x = 2911.85.

Divide both sides by 3

x = $970.62

The advertising rates in this journal for a full-page add is $970.62 and for a half-page ad is $685.63

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

the answer is 1030 it's very simple math.