Halla el mayor número de niños entre los cuales se pueden repartir simultáneamente 32,48 y 56 panes, de manera que en cualquiera de los casos cada uno reciba la misma cantidad. ¿ cuántos panes recibirá cada niño?

8 loaves

Step-by-step explanation:

Possible english translation:

Find the largest number of children among whom 32.48 and 56 loaves can be distributed simultaneously, so that in either case each receives the same amount. How many loaves will each child receive?

Solution:

The max amount each one will receive from either 32, 48, or 56 loaves would basically be the HCF (highest common factor) of the 3 numbers.

To get HCF of the 3 numbers given, we follow the rule below:

We show this below:

32/2 = 16/2 = 8/2 = 4/2 = 2

So,

32 =

48/2 = 24/2 = 12/2 =6/2 = 3

So,

48 =

56/2 = 28/2 = 14/2 = 7

56 =

Common factor is only "2" (in all 3 numbers) and the lowest powered one is 2^3, so the HCF is 8

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]