Given that the value of b can never equal to -1 determine if the equation are intersecting , parallel , or coincident
X+y= ab
Bx-y= a

The equations are intersecting lines

Step-by-step explanation:

The given equations are:

Add both equations:

Factor

Since b≠-1, we can 1+b is different from zero.

This means that:

From equation 1,

The two equations intersect at:

(a,ab-a)

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1