Arectangular deck is 12 ft by 14 ft. when the length and width are increased by the same amount, the area becomes 288 sq. ft. by how much were the dimensions increased?

The solution would be like this for this specific problem:

Dimensions of the rectangle = 12 + x and 14 + x

(12 + x) (14 + x) = 288

x² + 26x + 168 = 288

x² + 26x − 120 = 0

(x + 30) (x − 4) = 0

x=−30, x =4

The dimensions increased by 4 feet.

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4

Step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet