Help me! what do I put in this box??
Suppose ABCD is a rhombus such that the angle bisector of ∠ABD meets
AD at point K. Prove that m∠AKB = 3m∠ABK.

23

step-by-step explanation:

not sure but it may be b, as i said i'm not sure.

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9

v=1788.75

step-by-step explanation:

i belive that is the answer