One angle of a triangle measures more than the second. The measure of the third angle is twice the sum of the first two angles. What is the measure of each angle?

Step-by-step explanation:

Let

x ----> the measure of one angle of the triangle

y ---> the measure of the second angle

z ----> the measure of the third angle

we know that

The sum of the measure of the interior angles in any triangle must be equal to 180 degrees

-----> equation A

One angle of a triangle measures  10 degrees more than the second

----> equation B

The measure of the third angle is twice the sum of the first two angles

---> equation C

substitute equation B in equation C

----> equation D

substitute equation D and equation B in equation A

solve for y

Find the value of x

Find the value of z

therefore

what?

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)