3c+15=c+7

can you please explain how to do this equation plz :)

c = -4

Step-by-step explanation:

Solve for c:

3 c + 15 = c + 7

Subtract c from both sides:

(3 c - c) + 15 = (c - c) + 7

3 c - c = 2 c:

2 c + 15 = (c - c) + 7

c - c = 0:

2 c + 15 = 7

Subtract 15 from both sides:

2 c + (15 - 15) = 7 - 15

15 - 15 = 0:

2 c = 7 - 15

7 - 15 = -8:

2 c = -8

Divide both sides of 2 c = -8 by 2:

(2 c)/2 = (-8)/2

2/2 = 1:

c = (-8)/2

The gcd of -8 and 2 is 2, so (-8)/2 = (2 (-4))/(2×1) = 2/2×-4 = -4:

c = -4

c = -4

Step-by-step explanation:

3c+15=c+7

Subtract c from both sides

3c - c + 15 = c - c + 7

2c + 15 = 7

Subtract 15 from both sides

2c + 15 - 15 = 7 - 15

2c = -8

Divide both sides by 2

2c/2 = -8/2

c = -4

I hope this was helpful, please rate as brainliest

i believe it's a.

i'm not sure on this one, most likely correct.

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)