A quadratic function can be written in the form h(x)=k(x-a)(x-b), where a and b are the zeros of the function. Write h(x) in standard form if its zeros are -3 and -5 and k is 3.

h(x)=3x^2 +24x+45

Step-by-step explanation:

a=-3, b=-5, k=3,

h(x)=k(x-a)(x-b)

h(x)=3(x-(-3))(x-(-5))

h(x) =3(x+3)(x+5)

h(x)=3(x*x+x*5+3*x+3*5)

h(x)=3(x^2 +5x+3x+15)

h(x)=3(x^2 +8x+15)

h(x)=3x^2 +24x+45

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

idk

step-by-step explanation: