How many unstable pairs are present in the matching indicated by the asterisks? Note that if PP is the set of proposing men and AA is the set of accepting women, then a pair is of the form (p, a)(p, a) such that p∈P and a∈A. As such, every man/woman pair only counts as a single pair, i. e. (Chad, Becky) counts as a pair but (Becky, Chad) does not.

Figure it out your self

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60