The mean income per person in the United States is $50,000, and the distribution of incomes follows a normal distribution. A random sample of 10 residents of Wilmington, Delaware, had a mean of $60,000 with a standard deviation of $10,000. At the 0.05 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average

Yes. There is sufficient eveidence to support  the claim that Wilmington resident's earn more than the national average

Step-by-step explanation:

Given the following;

#We set our hypothesis as:

The rejection region of either hypothesis:

, we determine the critical values for this probability in the T distribution table;

=>We reject for all values greater than 1.833, t>1.833.

#We now determine the value of the test statistic as:

We find that:

Hence, there is sufficient eveidence to support  the claim that Wilmington resident's earn more than the national average.

50x5=$250

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