The length of country and western songs is normally distributed and has a mean of 200seconds and a standard deviation of 25 seconds. Find the probability that a randomselection of 9 songs will have mean length of 188.58 seconds or less. Assume thedistribution of the lengths of the songs is normal.

Probability = 0.1039

Step-by-step explanation:

To solve this problem, we have to find the t- value.

From the question,

Mean; μ = 200

Standard deviation; σ = 25

N = 9

Distribution of the t statistic (also known as the t score), whose values are given by:

t(x) = (x - μ)/ [σ/√(n)]

x = sample mean

μ = Population mean

n = sample size

σ = standard deviation

In this question,

x = 188.58

μ = 200

n = 9

σ = 25

Plugging in these values, we now have;

t(188.58) = (188.58 - 200)/ [25/√(9)]

t(188.58) = -1.3704

Now, Degree of Freedom is given by,

DF = n - 1

So,DF = 9 - 1 = 8

So,for P(x < 188.58) with degree of freedom of 8 and and t value as -1.3704, from the t-distribution table and online calculator, we have a value of 0.1039

answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

ask for details followreport by buttfacelily 2 minutes ago

answers

rauschg

rauschg · hand

know the answer? add it here!

step-by-step explanation:

i’m here for points.