Solve x2 + 12x = -11 by completing the square. Which is the solution set of the equation?
{-11, -1}
{-11, 1}
{11, -1}
{11, 1}
O

{-11, -1}

Step-by-step explanation:

x^2 +12x = -11

Take the coefficient of x

12

Divide by 2

12/2 =6

Then square it

6^2 = 36

Add this to both sides

x^2 +12x+36 = -11+36

(x+6)^2 = 25

Take the square root of each side

sqrt((x+6)^2) = ± sqrt(25)

x+6 = ± 5

Separate into two equations

x+6 = 5           x+6=-5

Subtract 6 from each side

x+5-6 = 5-6          x+6-6 = -5-6

x=-1                              x=-11

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5

homozygous. one is homozygous, while two is heterozygous.