Caleb went into a cave. The light intensity (in candela per square meter, or \text{cd/sq. m}cd/sq. mstart text, c, d, slash, s, q, point, space, m, end text) as a function of depth inside the cave (in \text{m}mstart text, m, end text) is graphed. What is the approximate average rate at which the light intensity decreases, as Caleb goes from a depth of 5\text{ m}5 m5, start text, space, m, end text to a depth of 14\text{ m}14 m14, start text, space, m, end text?

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation:

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )

1. minimum

2. 6400

3. eight

hope this !