Write an equation of the line that passes through (3, 5) and is perpendicular to the graph of y = -3x + 7 write your final equation in slope-intercept form

y = x/3 + 4

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m represents the slope of the line.

c represents the y intercept.

The equation of the given line is

y = - 3x + 7

Comparing with the slope intercept form, slope = - 3

If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line.

Therefore, the slope of the line passing through (3, 5) is 1/3

To determine the y intercept, we would substitute m = 1/3, x = 3 and y = 5 into y = mx + c. It becomes

5 = 1/3 × 3 + c

5 = 1 + c

c = 5 - 1 = 4

The equation becomes

y = x/3 + 4

man its nopq i just guessed and got it right so uhh

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step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.