A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football players, 52% are basketball players, and 9% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that he is either a football player or a basketball player?

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player =

The probability that athlete is a basketball player =

The probability that athlete is both basket ball player and  football player =

We have to find the probability that an athlete chosen is either a football player or a basketball player .

Now we know that;

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

answer: 0.1,0.85

step-by-step explanation:

2+2 obliviously is 4.