A wrench 0.1 meters long lies along the positive yy-axis, and grips a bolt at the origin. A force is applied in the direction of ⟨0,2,−4⟩⟨0,2,−4⟩ at the end of the wrench. Find the magnitude of the force in Newtons needed to supply 100 Newton-Meters of torque to the bolt.

Therefore the magnitude of the applied force is N.

Step-by-step explanation:

Torque: Torque is the cross product of force and the distance of applied force  from the rotational axis.

Where is angle between F and r.

Newton-meter is the S.I unit of torque.

Along the positive y axis, the wrench lies .

The length of wrench is 0.1 m.

  [ since the vector lies on y axis]

The direction of applied force is along the vector <0,2,-4>.

Then the angle between and <0,2,-4> = the angle between F and .

We know that,

We know that,

Here = 100 N-m, and

Now

Therefore the magnitude of the force is N.

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

idc

step-by-step explanation:

idk