2 POINTS) Using the calculation for damage and defects discussed in lecture, calculate the number of standardized sets that must be planned for in order to have 7,500 sets available to the customer each month. (Choose the closest answer) Group of answer choices 7431 7763 7604 7514 7798 7831 7708 7691 7512 7756

7431, 7763, 7604

Step-by-step explanation:

Number of standardized size Z

The observation 7500

Mean U

Standard deviation S

Group 1

7431 7763 7604

U = (7431 + 7763 + 7604)/4

U = -0.736

Z = (X - U)/S

Z = (7500 - 7599.3)/135 = -99.33/135

Z = - 0.736

For first group

Group 2

7514 7798 7831 7708

U = (7514+ 7798+ 7831 +7708 )/4

U = 7712.75

S = 123.27

Z = (X - U)/S

Z = (7500- 7712.75)/123.27 = -212.15/123.27

Z = - 1.721

For second group

Group 3

7691 7512 7756

U = (7691 + 7512 +7756)/3

U = 7652.7

S = 102.84

Z = (X - U)/S

Z = (7500- 7652.7)/102.84 = -152.7/102.84

Z = - 1.4848

For third group

Z1>Z3>Z2

The first group is the answer

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: