An amusement park sells adult tickets and children tickets, with adult tickets costing $5 and children's tickets costing $3 if Ed bought 15 tickets and spent a total of $57, how many children's tickets did he buy?

He buy 6 children tickets

Step-by-step explanation:

First we have to perform 2 equations, one indicating the number of tickets and the other the total amount

x = Adult tickets

y = Children tickets

x + y = 15

x * $5 + y * $3 = $57

we clear the x from the first equations

x + y = 15

x = 15 - y

we replace the value of x in the second equation with (15 - y) and solve

x * $5 + y * $3 = $57

(15 - y) * 5 + y * 3 = 57

75 - 5y + 3y = 57

-5y + 3y = 57 - 75

-2y = -18

y = -18/-2

y = 9

we replace y in the first equation

x = 15 - y

x = 15 - 9

x = 6

He buy 6 children tickets

i would pic false cause it goes down towards negative

step-by-step explanation:

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it