The sum of two numbers is 61 and the difference is 3 what are the numbers

Step-by-step explanation:

Let x = number

Let y = second number

We know that there are two true equations from this. Here is shown below the equations.

x + y = 61

x + 3  = y

We could use the substitution method for finding the numbers. After that, we continue on to solve to find the first number.

x + (x+3) = 61

2x + 3 = 61

2x = 58

2x/2 = 58/2

x = 29

Now that we know that the first number is 29, plug it in to the second equation to find the second number.

x + 3 = y

29 + 3 = y

y = 32

Proof that these numbers are the correct

32 + 29 = 61

61 = 61 (Which is true!)

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g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)