A car's cooling system has a capacity of 20 quarts. Initially, the system contains a mixture of 3 quarts of antifreeze and 17 quarts of water. Water runs into the system at the rate of 1 gal min , then the homogeneous mixture runs out at the same rate. In quarts, how much antifreeze is in the system at the end of 5 minutes? (Round your answer to two decimal places.)

After 5 minutes, there will be 0.98 quarts of antifreeze and 19.02 quarts of water in the tank.

Since a car's cooling system has a capacity of 20 quarts, and initially, the system contains a mixture of 3 quarts of antifreeze and 17 quarts of water, and water runs into the system at the rate of 1 gal min, then the homogeneous mixture runs out at the same rate, to determine, in quarts, how much antifreeze is in the system at the end of 5 minutes, the following calculation must be performed:

1 quart = 0.25 gallons 3 x 0.25 = 0.75 gallons of antifreeze 17 x 0.25 = 4.25 gallons of water 1 = 0.2 of 5 Minute 1 = 0.75 x 0.8 = 0.6 Minute 2 = 0.6 x 0.8 = 0.48 Minute 3 = 0.48 x 0.8 = 0.384 Minute 4 = 0.384 x 0.8 = 0.3072 Minute 5 = 0.3072 x 0.8 = 0.24576 0.24576 gallons = 0.98 quarts

Therefore, after 5 minutes, there will be 0.98 quarts of antifreeze and 19.02 quarts of water in the tank.

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1.10 quarts

Step-by-step explanation:

We are given that

Capacity of system=20 quarts=

1 gallon=4 quarts

Initially mixture contains

Antifreeze=3 quarts=

Water=17 quarts=

Water runs in to the system=1gal/min

We have to find the antifreeze in the system at the end of 5  minutes.

Concentration inflow=0

Let Concentration outflow=x

Rate of system=Concentration inflow(water inflow rate)-Concentration outflow(water outflow rate)

Taking integration on both sides

Using formula

Substitute t=5

Hence, in the end of 5 minute ,the antifreeze in the system=1.10 quarts

Then why is the question on here if you know the answer

1.5 pounds because you put 9over 6 and then divide by 6