A rectangle is 3 times as long as it is wide. If the length is increased by 6 and the width is increased by 8, its area is increased by 108. Find the original dimensions.

Length = 6, Breadth = 2

Step-by-step explanation:

Given:

A rectangle is 3 times as long as it is wide.

If the length is increased by 6 and the width is increased by 8, its area is increased by 108.

Question asked:

Find the original dimensions.

Solution:

Let width of rectangle =

As given that a rectangle is 3 times as long as it is wide.

Length of rectangle =

Now, as given that length is increased by 6 and the width is increased by 8,

New length =

New breadth =

New area =

As new area increased  by 108, we can say:-

New area - old area = 108

Subtracting both sides by 48

Dividing both sides by 30

Width of rectangle = = 2

Length of rectangle = =

Therefore, original length of rectangle was 6 and original width of rectangle was 2.

6 meters

step-by-step explanation: