Write an equation in slope-intercept form for the line that satisfies the following condition. passes through (20, 1), parallel to the graph of y = 6x + 6

Slope-intercept form:  y = mx + b  

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they have to have the same slope.

y = 6x + 6    The slope of this line is 6, so the parallel line's slope is also 6.

Now that you know m = 6, substitute/plug it into the equation:

y = mx + b         Plug in 6 for "m" in the equation  

y = 6x + b     To find "b", plug in the point (20, 1) into the equation

1 = 6(20) + b

1 = 120 + b       Subtract 120 on both sides to get "b" by itself

1 - 120 = 120 - 120 + b

-119 = b         Now that you know b = -119, plug it into the equation

y = 6x - 119

took the test it's 94

center= (-2,0)

radius= sqrt2/2

step-by-step explanation: