What is the value of A when we rewrite 3.14^159x as A^x?

The rule we'll use is

p^(q*r) = (p^q)^r

The exponents have been rearranged a bit.

In this case, p = 3.14, q = 159 and r = x, so,

p^(q*r) = (p^q)^r

3.14^(159*x) = (3.14^159)^x

This is in the form A^x with A = 3.14^159

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

answer

106 emergencies

step-by-step explanation: