Mathematics, 31.03.2020 03:18 lwattsstudent
5.3.24 A is a 3times3 matrix with two eigenvalues. Each eigenspace is one-dimensional. Is A diagonalizable? Why? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. No. A matrix with 3 columns must have nothing unique eigenvalues in order to be diagonalizable. B. Yes. As long as the collection of eigenvectors spans set of real numbers Rcubed, A is diagonalizable. C. No. The sum of the dimensions of the eigenspaces equals nothing and the matrix has 3 columns. The sum of the dimensions of the eigenspace and the number of columns must be equal. D. Yes. One of the eigenspaces would have nothing unique eigenvectors. Since the eigenvector for the third eigenvalue would also be unique, A must be diagonalizable.
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Mathematics, 22.06.2019 00:10
Given: p: 2x = 16 q: 3x – 4= 20 which is the converse of p - q? if 2x + 16, then 3x - 4 20. if 3x –4 +20, then 2x # 16. lf 2x = 16, then 3x - 4 = 20. lf 3x – 4= 20, then 2x = 16. o o
Answers: 1
Mathematics, 22.06.2019 04:00
1.multiply and simplify if possible. √7x (√x − 7√7) 2. what is the simplest form of the radical expression? 33√2a−63√2a
Answers: 2
5.3.24 A is a 3times3 matrix with two eigenvalues. Each eigenspace is one-dimensional. Is A diagonal...
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