Mathematics, 31.03.2020 03:23 mfweldon64

Tyrone launches a toy rocket into the air with an initial upward velocity of 49 ft/s and an initial height of 0 ft. a. How long will it take the rocket to reach its maximum height? Round to the nearest hundredth. b. How high above the ground will it be? Round to the nearest tenth. c. What is the range of the function? d. Why is there a maximum point on the graph of this function?

Answers: 2

Show answers

Answers

Answer from: cristalcastro901

a) 1.52 s

b) 37.3 ft

c) [0,37.3] ft

d) Because it has a maximum whose value is 37.3 ft

Step-by-step explanation:

The motion of the toy rocket is a free fall motion (it is acted upon the force of gravity only), so it is subjected to a constant acceleration of

g=32.2 ft/s^2

towards the ground.

Therefore, the velocity of the rocket after time t is given by the following suvat equation:

v=u-gt

where

v is the final velocity

u is the initial velocity

t is the time

The rocket reaches the maximum height when the velocity becomes zero, so when

v = 0

Also, the initial velocity is

u = 49 ft/s

Therefore, solving the equation for t, we find the time:

$0=u-gt\\t=\frac{u}{g}=\frac{49}{32.2}=1.52 s$

In a motion with constant acceleration in free fall, the displacement of the object is given by

$s=ut-\frac{1}{2}gt^2$

where

u is the initial velocity

t is the time

g is the acceleration due to gravity

s is the displacement

In this problem, we have:

u=49 ft/s is the initial vertical velocity

t = 1.52 is the time taken to reach the maximum height

g=32.2 ft/s^2 is the acceleration due to gravity

So, the maximum height reaches by the rocket is:

$s=(49)(1.52)-\frac{1}{2}(32.2)(1.52)^2=37.3 ft$

The function that describes the height of the rocket at time t is:

$h(t) = h_0 + ut - \frac{1}{2}gt^2$

where

h_0 = 0ft is the initial height

t is the time

u = 49.7 ft/s is the initial velocity

g=32.2 ft/s^2 is the acceleration due to gravity

Substituting, we find the explicit expression:

h(t) = 49t-16.1t^2

The range of the a function corresponds to the set of values that the function (in this case, h(t)) can take.

In this problem, we know that the maximum value of h(t) is

$h_{max}=37.3 ft$ (part c)

Also, the value of h(t) must be positive, since the height of the rocket cannot be negative, so the minimum value is zero:

$h_{min}=0$

So the range of the function is:

[0,37.3] ft

This function represented on a graph would show a downward parabola, with maximum value at 37.3 ft.

The value of the maximum represents the maximum height of the rocket, as calculated in part b: therefore, the reason for which there is a maximum point on the graph of the function is that the function h(t) has a maximum at 37.3 ft, so it cannot assume larger values.

Answer from: Quest

Google it that might work

Answer from: Quest

If gravity is one third on mars then weight also one third on mars

Another question on Mathematics

Mathematics, 21.06.2019 12:30

Which statements are true of the graph of h(x) = ^3 square root of x-4 ? check all that apply.the domain of h(x) is the set of all real numbers. the range of h(x) is the set of all real numbers. for all points (x, h( h(x) exists if and only if x – 4 0. the graph of h(x) is a translation of f(x) down 4 units. the graph of h(x) intercepts the x-axis at (4, 0).

Answers: 1

Answer

Mathematics, 21.06.2019 16:30

Yoku is putting on sunscreen. he uses 2\text{ ml}2 ml to cover 50\text{ cm}^250 cm 2 of his skin. he wants to know how many milliliters of sunscreen (c)(c) he needs to cover 325\text{ cm}^2325 cm 2 of his skin. how many milliliters of sunscreen does yoku need to cover 325 \text{ cm}^2325 cm 2 of his skin?

Answers: 3

Answer

Mathematics, 21.06.2019 22:00

Given: △acm, m∠c=90°, cp ⊥ am , ac: cm=3: 4, mp-ap=1. find am.

Answers: 2

Answer

Mathematics, 21.06.2019 23:00

Find the distance between the pair of points a(-1,8) and b(-8,4)

Answers: 1

Answer

You know the right answer?

Tyrone launches a toy rocket into the air with an initial upward velocity of 49 ft/s and an initial...