Given: ABCD is a parallelogram.
Diagonals AC, BD intersect at E.
Prove: AE = CE and BE DE
Angles Segments Triangles Statements Reasons
ABCD is a parallelogram
ZABE and LODE
are alt. interior angles
ZBCE and ZDAE
are alt. interior angles
LCBE and ZADE
are alt. interior angles
Statements
Reasons
D
Assemble the proof by dragging tiles to
the Statements and Reasons columns.

Use this data in the problem below. follow the steps carefully. round to the nearest tenth. lot 3: week 1: 345 week 2: 340 week 3: 400 week 4: 325 step 1. jim enters the data and calculates the average or mean. step 2. jim calculates the deviation from the mean by subtracting the mean from each value. step 3. jim squares each deviation to remove negative signs. step 4. jim sums the squares of each deviation and divides by the count for the variance. step 5. jim takes the square root of the variance to find the standard deviation.

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What is the solution to the system of equation graphed belowa.(0,-4)b.(2,5),1),-3)