Find the value of BCF angle.

triangleBFCBis an isosceles triangle

angleBFC=90°

angle FBC and angle BCF are equal

let angle FBC=x,angleBCF=x

the sum of angles in a triangle=180°

90+x+x=180°

90+2x=180

2x=180-90

2x=90

divide both sides by 2

2x÷2=90÷2

x=45°

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

well if he bought them at 5 cedis each sold them at 7 cedis each then he would make a profit of 2 cedis of each book. if in total he made 150 cedis profit that means he sold 75 books. he lost 12 books at the start so that means he originally bought a total of 82 books.

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