Y =
x ² In (x)sin (2x)
find derivative please step by step and state which rules are used

Step-by-step explanation:

y=x² ln(x)sin 2x

taking log of both sides

log y=log(x² in(x)sin 2x)=log x²+log.ln (x)+log (sin2 x)

=2log x+log .ln(x)+log sin 2x

diff. w.r.t.x

1/y×(dy/dx)=2/x+(1/ln(x))×(1/x)+( 2 cos 2x/sin2x)

dy/dx=y[2/x+(1/x.ln(x))+2 cot 2x]

dy/dx=x² in(x) sin (2x)[2/x+1/xin(x)+2 cot 2x]

ok

step-by-step explanation:

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.