Plane B is flying 60mph faster than Plane A and can fly 3040 miles in the same amount of time it takes Plane A to fly 2800 miles. Find the amount of time it takes for each plane to travel their respective distances.

each plane travelled for 40 hours.

Step-by-step explanation:

Let x represent the speed of plane A. Plane B is flying 60mph faster than Plane A. It means that the speed at which plane B is flying is

(x + 60) mph

Plane B can fly 3040 miles in the same amount of time it takes Plane A to fly 2800 miles.

Time = distance/speed

Time taken by plane B to fly 3040 miles is

3040/(x + 60)

Time taken by plane A to fly 2800 miles is

2800/x

Since the time is the same, it means that

3040/(x + 60) = 2800/x

Cross multiplying, it becomes

2800(x + 6) = 3040x

2800x + 16800 = 3040x

3040x - 2800x = 16800

240x = 16800

x = 16800/240

x = 70 mph

The amount of time it takes for each plane to travel their respective distances is

2800/x = 2800/70 = 40 hours

dude   i don't even know. i've been trying for hours.

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form