Call the three angles of a triangle ∠1,∠2,∠3

The measure of ∠2 is forty degrees less than that of ∠1; the measure of ∠3 is ten degrees less than twice that of ∠1If x is the measure of ∠1, then which of the following equations would we need to solve in order to calculate the measures of the angles?

              ° is the measure of ∠.

              ° is the measure of ∠.

              ° is the measure of ∠.

Step-by-step explanation:

Given that,

      is the measure of ∠.

Now,

      The measure of ∠ is forty degree less than that of ∠, so () is the measure of ∠.

      The measure of ∠ is ten degree less than twice that of ∠, so () is the measure of ∠.

So,

     According to Angle sum property,

   Sum of the measures of the three angle of triangle is °.

Now,

        ∠ + ∠ + ∠ = °

        () + () + () = °

        °

        °

        °

So,

   ° is the measure of ∠.

   ° is the measure of ∠.

   ° is the measure of ∠.

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

6e14 is the answer.