Solve the system by elimination.. x+5y-4z=-10. 2x-y+5z=-9. 2x-10y-5z=0. a.) (5, –1, 0). b.) (–5, 1, 0). c.) (–5, –1, 0). d.) (–5, –1, –2).

You have three equations and assuming that the x, y, and z all have the same value for all equations. The best way to solve this is to start by rearranging the first equation to isolate X.

X+5y-4z=-10

X=4z-5y-10

Then you do the same with the second equation to isolate y.

2x-Y+5z=-9

2x+5z+9=Y

Substitute the X equation into the second rearranged equation.

2(4z-5y-10)+5z+9=Y

Simplify

8z-10y-20+5z+9=Y

13z-10y-11=Y … 13z-11=11Y … Y=(13z-11)/11

Substitute the X equation into the third equation.

2x-10y-5z=0

2(4z-5y-10)-10Y-5z=0

8z-10y-20-10Y-5z=0

Simplify

3z-20y=20

Insert the Y into the third equation

3z-20(13z-11)/11=20

3z-(260z+220)/11=20

Multiple by 11 & Simplify

33z-260z+220=220 … -227z=0

Divide this out and you will determine that Z =0 

Now put your Z value into the Y equation

Y=(13(0)-11)/11

Y=0-11/11

Y=-1

Finally, solve the first equation

X=4z-5y-10

X=4(0)-5(-1)-10

X=0+5-10

X=-5

Your answer is option C … (-5, -1, 0)

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

more detail

step-by-step explanation: