Find the zeros of the function in the interval [-2pi, 2pi].
f(x) = -4sin(x)

b)

Step-by-step explanation:

f(x)=-4sinx

0=-4sinx   /-4

0=sinx

x=  2kπ ; k∈R

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.