Determine the equation of a circle with a center at (-4,0) What is the equation of a circle with a center at (-4, 0)
that passes through the point (-2, 1) by following the that passes through the point (-2, 1)?
steps below.
O x2 + (y + 4)2 = 15
1. Use the distance formula to determine the radius:
d = (x2-x;)+ V2 -V,).
O (x – 1)2 + (y + 2)2 = 5
O (x + 4)2 + y2 = 5
2. Substitute the known values into the standard form:
(x – h) + (y – k)? = ?.
O (x + 2)2 + (y – 1)2 = 5
Intro
Done
(x+4)2 + y2 = 5

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation:

3.73 * 10^7 is the anser for ttm ur welcome < 3

step-by-step explanation: