Find the equation of the line whose slope is 2 and which passes through the point (-2,4)

Step-by-step explanation:

Given point (-2 , 4) and slope (m) = 2

The equation of line is given

y - y1 = m ( x - x1)

y - 4 = 2 ( x +2)

y - 4 = 2x + 4

2x + 4 + 4-y = 0

2x - y + 8 = 0

Which is the required equation

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47