What is the maximum height attained by the ball?

y=25

Step-by-step explanation:

The keyword in the question is "maximum", this tells you that you are looking for the vertex,(turning point of the graph, the highest point of the of the parabola). Since they are asking for the maximum height, and "t" represents seconds, you must find the "y" value.

Standard quadratic form is:

ax^2+bx+c

Use the vertex formula:

x=-b/2a

to find the "x" value of the vertex, then plug that value into the original equation as a substitute for "x".

Given y= 40t-16t^2

a=16, b=40

x=-40/2(-16)

x= 5/4 (or 1.25)

So,

y= 40(1.25) - 16(1.25)^2

y = 25

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24