Look at the figure. If m/_ L= 58, find /_ LKJ

64°

Step-by-step explanation:

KJ = KL, KM is common, and ∠JKM = ∠LKM, so the triangles are congruent.

∴ ∠ J = ∠L = 58°

The three angles of a triangle add up to 180°.

 ∠J + ∠L + ∠LKJ = 180°

58° + 58° + ∠LKJ = 180°

        116° + ∠LKJ = 180°

                  ∠LKJ = 180° - 116°

                            =  64°

i don't even know man. edge inuity be messing with us. i had to ask a question too.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐